Is this a bug in my Code?

Question

So I am making this tcp server for a game in Go in I have realized that clients get accepted without me even calling Accept()... If you run this example and try to connect to it via telnet or netcat you will realize that you still get accepted... package main import ( "fmt" "net" ) func main() { serv, err := net.Listen("tcp", "localhost:1200") if err != nil { fmt.Println(err) return } defer serv.Close() // Clients still get accepted, whats the reason? //sock := serv.Accept() fmt.Scanln() } // So we don't exit

Sumit Sharma · Accepted Answer

It is normal for the TCP stack to handle the handshake and establish the connection regardless of whether the client calls accept or not.

Sumit Sharma · Answer

Run it under strace, or the equivalent for your OS, and you'll see Go is sitting on read(2) and not completing any system calls despite the handshake completing for the other side of the socket.

Aditya Agrawal · Answer

Nop... Accepting the connection is always upto us... If we reach maximum clients then we simply come out of the infinite accept loop. There is a solution tho, you can close the server via Close() call on the server. This won't affect connected clients but this isn't a correct way of doing it. One should always be binded to the port they are using and this effectively gives up the port so some other program is free to use it.

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