Conditional variable declaration in golang?

Question

Is it possible to do conditional variable type declaration like this in Golang?
if isAdmin {
  var result NormalResult
} else {
  var result AdminResult
}

// do something to &result
doSomething(&result)

func doSomething(interface{}) {
  // something
}

The above does not work, but the ideas is that normalResult and adminResults are very similar structs and how would I go about doing this?

Thank you!

Gopher · Accepted Answer

Depending on what kind of similarities, you might have different options. Using embedded structs Depending on your structure, you might be able to use embedded structs. Let's say NormalResult is defined like this: type NormalResult struct { Name string Value int } And if AdminResult shares the same properties but just adds a few more of them (like UserId), you can choose to embed NormalResult into the AdminResult like this: type AdminResult struct { *NormalResult UserId int64 } Then you can also declare methods for NormalResult which will be promoted to AdminResult as well: func (r *NormalResult) doSomething() { // Doing something } And, no, it is not possible to have conditional types in Go as you suggested. A variable can only be of one type, be it NormalResult, AdminResult or interface{}

Go Language

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